Shaft Torsion Analysis
Calculate shear stress, torsion angle and torque for circular shafts under torsion — solid or hollow cross-section
Inputs
Formula Interpretation
Polar Moment — Solid Circle
Sum of ρ²Δa over the full cross-section. For a solid circle of diameter d: .
Section Modulus — Solid Circle
Z_p = I_p / r. For a solid circle: . Maximum shear stress occurs at the outer radius.
Polar Moment — Hollow Circle
For hollow circle (outer d₂, inner d₁): . Hollowing removes the low-stress core while retaining most stiffness.
Section Modulus — Hollow Circle
For hollow circle: . Dividing by the outer radius d₂/2 gives the maximum-stress section modulus.
Shear Stress from Torque
Design formula ⑦: the maximum shear stress is proportional to torque and inversely proportional to .
Shear Stress from Angle (Direct)
Formula ②: shear stress from the torsion angle. is proportional to and outer radius , and inversely proportional to shaft length.
Torsion Angle
Formula ③: torsion angle in radians. Multiply by 57.3 to convert to degrees.
Stiffness Limit
Stiffness criterion: the torsion angle per unit length must not exceed 0.25 °/m (i.e. 1/4° per metre). This is the standard rigidity limit for transmission shafts.
Torque from Power
Formula ④: exact derivation T = P·60/(2π·n). With in kW and in rpm, T ≈ 9550·P/N in N·m.
Knowledge Points
Torsional Shear Strain
When a shaft is twisted, any fibre parallel to the axis shears into a helix. The shear strain γ = r·θ/l relates the outer radius r, total torsion angle θ (rad) and shaft length l. The linear distribution means γ = 0 at the neutral axis and γ_max at the outer surface.
Polar Moment of Inertia
I_p = Σρ²Δa measures the resistance of a cross-section to twisting — analogous to the second moment of area for bending. A hollow shaft removes material near the axis (low ρ, small contribution) and is therefore nearly as stiff as a solid shaft at significantly lower weight.
Stiffness Requirement
For transmission shafts, the allowable stiffness is typically 0.25 °/m (or 1/4° per metre) to avoid vibration and misalignment. When this condition governs, it may require a larger diameter than the strength condition alone would demand.
Worked Example
A solid circular shaft of diameter 30 mm, length 500 mm, has a torsion angle of 1° when twisted. Find the shear stress. Given: .
Step 1 — Shear Stress Directly from Angle (Formula ②)
Step 2 — Verify via Section Properties
Step 3 — Verify Torsion Angle (Formula ③)
Result: τ = . All three approaches give the same answer, confirming the consistency of formulas ①②③.
Extended Knowledge
- •For shafts with multiple torque inputs (e.g. a gearbox), draw a torque diagram first: the torque varies along the shaft length and the maximum value governs the design.
- •Saint-Venant''s torsion applies only to circular cross-sections. For non-circular sections (rectangular, I-beam, etc.) the shear stress is non-uniform and separate theories (Prandtl''s stress function, finite element) are required.
- •In fatigue-loaded shafts, the allowable shear stress [τ] must account for stress concentration factors at keyways, grooves and press-fit interfaces. Combined bending and torsion is analysed using the von Mises or Tresca criterion.